There are 12 ways the player can make 11 shots and miss one shot, and there is 1 way the player can make all shots, so there is a total of 13 ways that the player makes at least 11 out of 12 free throws.
The total number of possibilities for the free throws is 2^12 = 4096
Therefore, the probability that the player makes at least 11 out of 12 free throws is 13/4096
I believe its the second one because it say four times the number wich the number is the y and it is = too the number wich is y and increased going up are adding by 9. hope that helped.
