Answer:
A' = 6(3t +1)
Step-by-step explanation:
The area is the square of the side length, so ...
A = (3t +1)²
The derivative with respect to t is then
A' = 2(3t +1)·(3) = 6(3t +1)
If you like, you can multiply out the area expression first, then differentiate.
A = 9t² +6t +1
A' = 18t +6
This can be factored, if you like, to ...
A' = 6(3t +1)
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Answer:
<em>Thus, the transformation from ABC to A'B'C' is a reflection over the x-axis.</em>
<em>Choice 1.</em>
Step-by-step explanation:
<u>Reflection over the x-axis</u>
Given a point A(x,y), a reflection over the x-axis maps A to the point A' with coordinates A'(x,-y).
The figure shows triangles ABC and A'B'C'. It can be clearly seen the x-coordinates for each vertex of both triangles is the same and the y-coordinate is the inverse of it counterpart. For example A=(5,3) and A'=(5,-3)
Thus, the transformation from ABC to A'B'C' is a reflection over the x-axis.
Choice 1.
Answer:
2
Step-by-step explanation:
because you are not behind the three point line
Note that this a right-angled triangle with the right angle at Y.
<span>Use coordinates of the point to find XY and YZ </span>
<span>XY = 21 - (-3) </span>
<span>= 24 </span>
<span>YZ = 4 - (-6) </span>
<span>= 10 </span>
<span>Use Pythagoras theorem to XZ </span>
<span>XZ = sqrt[24^2 + 10^2] </span>
<span>= 26 </span>
<span>Perimeter = 26 + 24 + 10 </span>
<span>= 60</span>
