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2 years ago

How to solve for a squared in the pythagorean

1 answer:

8 0

There are a few places to go when you want to know something, maybe like this
http://www.wikihow.com/Solve-Pythagoras-Theorem-Questions

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May you please help me for part b for brainliest,

olya-2409 [2.1K]

Answer:

Very certain it is C

Step-by-step explanation:

There are no points on the graph line itself so I cannot really confirm this but i am 70% sure

7 0

2 years ago

Help me plz !!!?!?!?!

olganol [36]

I believe the answer is the second one I am in the same class.

5 0

2 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago

A package states that there are 60 calories in 12 crackers

kvv77 [185]

Answer: 5 calories = 1 cracker

Step-by-step explanation:

60:12 = 5:1

60 calories and 12 crackers = 5 calories and 1 cracker

7 0

2 years ago

Is the relation a function? {(-1,7), (9,4), (3,-2), (5,3), (9,1)}

guapka [62]

Answer:

Yes. it is a function

Step-by-step explanation:

None of the x's axis are the same

7 0

2 years ago