Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDLcholesterol?
sample mean = x-bar = 4.7
ME = 1.96*15.6/sqrt(43) = 4.663
95% CI: 4.7 - 4.663 < u < 4.7 + 4.663
You can factor this by taking out the GCF (greatest common factor).
In the expression, the greatest common factor between the two terms is 5.
Take out 5:
5(2b + 5)
Is it possible to factor 2b + 5 even more?
No. So, your answer is D. 5(2b + 5).
Answer:
B, x≥2
Step-by-step explanation:
54 - 10x ≤ 20 + 7x - subtract 20
34 - 10x ≤ 7x - add 10x to 7x
34 ≤ 17x - divide 34 by 7
2 ≤ x - flip the equation - x ≥ 2
Hope this is helpful!
Answer:
Step-by-step explanation:
Look at the number and the angles
Multiple the angles all together that's how u find x
Answer:
73.4846922835 = 73.5 and no it is not a perfect square 5400/100 = 54
