Information Given: She has 12 groups of sheep, 3 groups of cows and 2 groups of pigs. Question asks: There are 150 more sheep than pigs. How many cows has she got?
They figured 150 more sheep than pigs from 2 pigs X 75 sheep=150 lambs of 12 groups of sheep.
150 lambs/3 groups of cows=50 cows.
She has 50 cows from 3 groups of cows.
Answer:
P= Rs 60000
A= Rs 79860
T=1 & 1/2 year = 3/2 years
= 3/2 x 2 = 3 half years
R= ?
Applying the formula A= P (1+r/100)^T
79860 = 60000 (1+ r/100)^3
79860/60000 = (1+r/100)^3
1331/1000 = (1+r/100)^3
root(3)(1331/1000) = (1+r/100)
11/10 = 1+r/100
11/10 -1 = r/100
1/10 = r/100
r= 10 %
Step-by-step explanation:
Answer:
I will take a look
Step-by-step explanation:
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Answer:
So calculate the negative answers and turn them into absolute value. Then put them in order.
Step-by-step explanation:
Answer:
x=6 y=-9
Step-by-step explanation:
- Layer the equations on each other as you would in a subtraction problem:
8x + 2y=30
7x + 2y=24
- Subtract the equation just like you would normally. This should leave 1x=6 or x=6.
- Now that you have your x value, plug it in as x for one of the equations. For the 2nd equation, this leaves:
42+2y=24 then
2y=-18 then
y=-9
- Double check your y value by plugging x=6 into the first equation. This should also leave y=-9.
