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nevsk [136]
4 years ago
15

What is the domain of y = log Subscript 5 Baseline x?

Mathematics
2 answers:
Marina CMI [18]4 years ago
6 0

Answer:

For this case we have this function given:

y = log_5 (x)

In order to find the domain we need to find the possible values of x that the function can assume.

And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

x> 0

And we can write this in formal notation as:

D = [ X \in R | X>0]

And the best answer for this case would be:

all real numbers greater than 0

Step-by-step explanation:

For this case we have this function given:

y = log_5 (x)

In order to find the domain we need to find the possible values of x that the function can assume.

And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

x> 0

And we can write this in formal notation as:

D = [ X \in R | X>0]

And the best answer for this case would be:

all real numbers greater than 0

lutik1710 [3]4 years ago
3 0

Answer:

The answer is all numbers greater than 0

Step-by-step explanation:

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shusha [124]

Answer:

The answer to your question is y = -11/2x - 19

Step-by-step explanation:

Data

Point (-4, 3)

⊥ to the line x- intercept of 22 and y-intercept of -4.

Process

1.- Find the equation of the perpendicular line

This line has passes through the points  (22, 0) and (0, -4)

Slope = \frac{-4 - 0}{0 - 22} = \frac{-4}{-22} = \frac{2}{11}

2.- Find the slope of the new equation

Slope = \frac{-11}{2}    because the lines are perpendicular

3.- Find the equation of the new line

            y - 3 = -11/2 (x + 4)

            y - 3 = -11/2x - 44/2

            y - 3 = -11/2 x - 22

            y = -11/2 x - 22 + 3

            y = -11/2x - 19

See the graph below

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Which ordered pair is a solution if the equation ?
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Step-by-step explanation:

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Step-by-step explanation:

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4 years ago
write a quadratic function in vertex form whose graph has the vertex (1,0) and passes through point (2,-17)
kobusy [5.1K]

Answer:

\displaystyle f(x) = -17(x-1)^2

Step-by-step explanation:

We want to write a quadratic function in vertex form whose vertex is (1, 0) and passes through the point (2, -17).

Recall that vertex form is given by:

\displaystyle f(x) = a(x-h)^2 + k

Where (<em>h</em>, <em>k</em>) is the vertex and <em>a</em> is the leading coefficient.

Since our vertex is at (1, 0), <em>h</em> = 1 and <em>k</em> = 0:

\displaystyle f(x) = a(x-1)^2

It passes through the point (2, -17). Hence, when <em>x</em> = 2, <em>y</em> = -17:

\displaystyle (-17) = a((2)-1)^2

Solve for <em>a: </em>

<em />\displaystyle a = -17<em />

<em />

In conclusion, our quadratic function in vertex form is:

\displaystyle f(x) = -17(x-1)^2

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