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Leno4ka [110]
3 years ago
8

1/2 + 1/3 hElP!!!!!!!

Mathematics
1 answer:
liubo4ka [24]3 years ago
4 0
First you need to get the same denominator on both fractions. You can do this buy multiplying the fraction by the other fractions denominator:

1/2 + 1/3

1/2 x 3 = 3/6

1/3 x 2 = 2/6

So the new expression with the same denominators is:

3/6 + 2/6

Then just add the numerators:

5/6
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Find Sin A, Cos A, and Tan A given the following triangle.
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Answer:

A

Step-by-step explanation:

sin A=(opposite side)/hypotenuse=a/c

cos A=(adjacent side)/hypotenuse=b/c

tan A=(opposite side)/(adjacent side)=a/b

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3 years ago
I WILL MARK YOU BRAINLIEST PLS HELP!!! The image below shows two dilated figures with lines AB and A’B’ drawn. If the larger fig
geniusboy [140]

Answer:

Lines AB and A'B' are similar, line A'B' being three times the size of line AB. They would not be congruent since a dilation isn't a rigid transformation but they would be similar. Their lengths would also be expressed in the form of a ratio which would be 1:3 if you do AB to A'B' and 3:1 if you do A'B' to AB. Hope this helped! :)

Step-by-step explanation:

The relationship between two lines AB and A’B’ is A'B'=3AB.

It is given that in the given figure larger figure was dilated using a scale factor of 3. It means the smaller and larger figures are similar and there corresponding sides are in the ratio 1:3.

The line AB connecting the two points of the smaller figure and line A'B' connecting the two points of the larger figure.

Since A'B' is corresponding line segment of AB in larger figure, therefore the ratio of AB to A'B' is 1:3.

By cross multiplication we get

The length of segment A'B' is 3 times of AB.

MARK ME BRAINLIEST!

6 0
3 years ago
Spencer wrote the following paragraph proof showing that rectangles are parallelograms with congruent diagonals. Quadrilateral R
Komok [63]

We have to prove that rectangles are parallelograms with congruent Diagonals.

Solution:

1. ∠R=∠E=∠C=∠T=90°

2. ER= CT, EC ║RT

3.  Diagonals E T and C R are drawn.

4. Shows Quadrilateral R E CT is a Rectangle.→→[Because if in a Quadrilateral One pair of Opposite sides are equal and parallel and each of the interior angle is right angle than it is a Rectangle.]

5.  Quadrilateral RECT is a Parallelogram.→→[If in a Quadrilateral one pair of opposite sides are equal and parallel then it is a Parallelogram]

6. In Δ ERT and Δ CTR

(a) ER= CT→→[Opposite sides of parallelogram]

(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]

(c) Side TR is Common.

So, Δ ERT ≅ Δ CTR→→[SAS]

Diagonal ET= Diagonal CR →→→[CPCTC]

In step 6, while proving Δ E RT ≅ Δ CTR, we have used

(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]

Here we have used ,Option (D) : Same-Side Interior Angles Theorem, which states that Sum of interior angles on same side of Transversal is supplementary.

6 0
3 years ago
Read 2 more answers
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