How do i do numer 1 and 3.?!?!?!?!?!

Mathematics

1 answer:

Anna11 [10]3 years ago

8 0

To solve each question, all you've got to do is add the two numbers together and then graph the result on the number line.

1.) -3 +(-1.5)
Add 3 to -1.5. It would be the same as subtracting 1.5 from -3(-3 - 1.5)
Final Answer: -4.5
Or, since you are using a number line, start on -3 and go left 1.5 units and you will land on the -4.5 point. You go to the left because you are adding a negative number..

2.) 1.5+3.5
Add
Final Answer: 5
Or, since you are using a number line, start on 1.5 and go to the right 3.5 and you will land on 5. You go to the right because you are adding a positive number.

3.) 1/4 + 1/2
Multiply 1/2 by 2 to make both fractions have the same denominator
1/4 + 2/4
Add
Final Answer: 3/4
Or, since you are using a number line, start on 1/4 and go up 2/4 and you will land on 3/4 as the result.

4.) -1 1/2 + (-1 1/2)
Add -1 1/2 to -1 1/2. This would be the same as subtracting 1 1/2 from -1 1/2(-1 1/2 - 1 1/2)
Final Answer: -3
Or, since you are using a number line, start on -1 1/2 and go to the left 1 1/2 and you will land on the -3 point.

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Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

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Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$