Answer:
Probability of winning first situation: 0.0793
Probability of winning second situation: 0.0146
You should go with the first option
Step-by-step explanation:
See attached photo for answers. For this situation you need to identify p-hat, p, q and n.
P-hat, p, and q all stay the same for both situations, only n changes.
p-hat is the proportion of green balls we want, which is 0.7
p = 98/159 = 0.62
q = 0.38 because q = 1 - p, which in this case is q = 1 - 0.62 = 0.38
n = 73 for the first situation, and n = 175 for the second situation