At a new exhibit in the Museum of Science, people are asked to choose between 73 or 175 random draws from a machine. The machine
is known to have 98 green balls and 61 red balls. After each draw, the color of the ball is noted and the ball is put back for the next draw. You win a prize if more than 70% of the draws result in a green ball. [You may find it useful to reference the z table.] a. Calculate the probability of getting more than 70% green balls. (Round your intermediate proportion values and “z” value to 2 decimal places, and final answer to 4 decimal places.) b. Would you choose 73 or 175 draws for the game?
1 answer:
Answer:
Probability of winning first situation: 0.0793
Probability of winning second situation: 0.0146
You should go with the first option
Step-by-step explanation:
See attached photo for answers. For this situation you need to identify p-hat, p, q and n.
P-hat, p, and q all stay the same for both situations, only n changes.
p-hat is the proportion of green balls we want, which is 0.7
p = 98/159 = 0.62
q = 0.38 because q = 1 - p, which in this case is q = 1 - 0.62 = 0.38
n = 73 for the first situation, and n = 175 for the second situation
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The price of the tablet before the discount is $ 2667
<h3><u>Solution:</u></h3>Given that Marina paid $2,000 for a tablet PC after receiving a 25 percent discount
To find: The price of the tablet before the discount
Let "a" be the price of the tablet before the discount or original price
After receiving a 25 percent discount means 25 percent discount in original price
Discount = 25 % of original price
Discount = 25 % of "a"
Now we can say that,
<em>price of tablet after discount = price of the tablet before the discount - discount</em>
2000 = a - 0.25a
0.75a = 2000
a = 2666.67 ≈ 2667
Thus the price of the tablet before the discount is $ 2667