Answer:
The ball is in the air for approximately 3.27 seconds ⇒ answer A
Step-by-step explanation:
* Lets explain how to solve the problem
- The height of the ball is modeled by the function
h(t) = -4.9 t² + 16 t
- We need to find the time that the ball is in the air
- The ball is in the air from its initial position and then return to the
same position
- That means h(t) = 0 because h(t) represent the height of the ball
from its initial position
∵ h(t) = -4.9 t² + 16 t
∵ h(t) = 0
∴ 0 = -4.9 t² + 16 t
- Add 4.9 t² to both sides
∴ 4.9 t² = 16 t
- Subtract 16 t from both sides
∴ 4.9 t² - 16 t = 0
- Take t as a common factor
∴ t (4.9 t - 16) = 0
- Equate each factor by 0
∴ t = 0 and 4.9 t - 16 = 0
∵ 4.9 t - 16 = 0 ⇒ add 16 for both sides
∴ 4.9 t = 16
- Divide both sides by 4.9
∴ t = 3.2653
∴ t = 0 ⇒ initial position
∴ t = 3.2653 seconds ⇒ final position
* <em>The ball is in the air for approximately 3.27 seconds</em>
Answer:
The answer is True. Hope this helps. :)
Step-by-step explanation:
( 4 x 3 ) 3 + 5 - 10 = 4 x 3 + 5 - 10
- (4x3) = 12
- 3 + 5 = 8
- 4 x 3 = 12
- 3 + 5 = 8
This is basically an example of PEMDAS.
Perimeter
Equation
Multiplication
Division
Addition
Subtraction
(Multiplication is ahead of Addition, you multiply first)
Answer:
its 1 bc (7+3) =10 then 2×10= 20÷20=1
10/-5 = -2 so 5 - (-2)= 7
