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2 years ago

Simplify 4x2y + 12z2 + 6x2y – 2z.

Mathematics

2 answers:

yaroslaw [1]2 years ago

5 0

Divide all the terms by 2:
2xy + 12z + 3xy - z

Jlenok [28]2 years ago

3 0

10x2y + 12z2 – 2z

combine the like terms

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Find the largest whole number which is a factor of both 42 and 98

LuckyWell [14K]

Answer:

Step-by-step explanation:

hope this helps

5 0

2 years ago

Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square

ValentinkaMS [17]

Answer:

Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = $11\frac23\ yd^2$

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator, Add that to the numerator,Then write the result on top of the denominator.

$11\frac23\ yd^2$ can be Rewritten as $\frac{35}{3}\ yd^2$

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = $\frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2$

Amount of fabric left with Richard = $\frac56 \ yd^2$

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac56$

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}$

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project = $\frac{35-10}{12}= \frac{25}{12}\ yds^2$

$\frac{25}{12}\ yds^2$ can be rewritten as $2\frac{1}{12}\ yd ^2$

Hence Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

7 0

3 years ago

A large container holds 8 gallons of water. It begins leaking at a constant rate. After 48 minutes, the container has 5 gallons

Juliette [100K]

Answer:

The water is leaking at the rate of 0.0625 gal/min.

Step-by-step explanation:

Rate of change

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

The container holds 8 gallons of water and is leaking at a constant rate to be calculated later.

When 48 minutes have passed, the container has 5 gallons of water left. This means it has leaked 8 gallons - 5 gallons = 3 gallons.

Calculating the rate at which it's leaking:

$\displaystyle r=\frac{3\ gallons}{48\ min}$

r = 0.0625 gal/min

The water is leaking at the rate of 0.0625 gal/min.

5 0

3 years ago

Need help a through d

kobusy [5.1K]

it seems pretty tricky

7 0

2 years ago

Find the exact value of x

tresset_1 [31]

ΔABC and ΔCBD are similar. Therefore we have the proportion:

$\dfrac{AB}{BC}=\dfrac{BC}{BD}\\\\AB=6;\ BC=x;\ BD=2$

Substitute:

$\dfrac{6}{x}=\dfrac{x}{2}$ cross multiply

$(x)(x)=(6)(2)\\\\x^2=12\to x=\sqrt{12}\\\\x=\sqrt{4\cdot3}\\\\x=\sqrt4\cdot\sqrt3\\\\\boxed{x=2\sqrt3}$

6 0

3 years ago