PLEASE HELP ME!!!

The volume of a spherical sculpture is 256 ft³. Rhianna wants to estimate the surface area of the sculpture. To do the estimate,

Brrunno [24]

Answer:

192 $ft^2$

Step-by-step explanation:

Given that

Volume of spherical sculpture = 256 ft³

$\pi$ is used as 3.

To find:

Surface area of sculpture = ?

Solution:

First of all, let us learn about the formula for Volume and Surface Area of Sphere:

1. $Volume =\frac{4}{3}\pi r^3$

2. $Surface\ Area = 4\pi r^2$

Given volume is 256 ft³.

$256 = \dfrac{4}{3}\pi r^3\\\Rightarrow 256 = \dfrac{4}{3}\times 3 r^3\\\Rightarrow 256 = 4 r^3\\\Rightarrow r^3=64\\\Rightarrow \bold{r = 4\ ft}$

Now, let us put r = 4 in the formula of Surface Area to find the value of Surface Area:

$Surface\ Area = 4\pi 4^2 = 4 \times 3 \times 16 = \bold{192\ ft^2}$

So, approximate surface area of sculpture is 192 $ft^2$ .

3 0

3 years ago

What is the circumference of a dinner plate with a radious of 4.5 inches

____ [38]

Answer:

28.27 inches

Step-by-step explanation:

-Circumference of a circle is calculated using the formula:

$C=\pi D\\\\=2\pi r$

#Substitute for radius in the formula to solve for C:

$C=2\pi r\\\\=2\pi \times 4.5 \\\\=28.27 \ in$

Hence, the plate's circumference is 28.27 inches

4 0

3 years ago

Simplify the fraction 4t ^ 2 - 16 ÷8 ÷ t - 2 ÷6

Sedaia [141]

4t ^ 2 - 16 ÷8 ÷ t - 2 ÷6

=(4t ^ 2)-(16 ÷8 ÷ t)-(2 ÷6)

=(4t ^ 2)-(2/t)-1/3

=4t ^ 2-2/t-1/3

6 0

4 years ago

The area of a rectangular ceiling tile is 756 square inches. The perimeter is 114 inches. What are the dimensions of the tile?

kogti [31]

Here we need to use what we know about rectangles to make a system of equations.

By solving that system we found that the tile has a length of 36 inches and a width of 21 inches.

Remember that for a rectangle of length L and width W, the perimeter is:

P = 2*(L + W)

And the area is:

A = W*L

Here we know that the perimeter is 114 inches, then we can write:

114in = 2*(L + W)

We also know that the area is 756 in^2, then we can write:

756 in^2 = L*W

So we found two equations, which means that we have a system of two equations with two variables:

114in = 2*(L + W)

756 in^2 = L*W

To solve this, the first step is to isolate one of the variables in one of the equations, we can isolate L in the first equation:

114in = 2*(L + W)

114in/2 = (L + W)

57in = L + W

57in - W = L

Now that we have an expression equivalent to L, we can replace it in the other equation to get:

756 in^2 = L*W

756 in^2 = (57in - W)*W

Now we can solve this for W.

756 in^2 = W*57in - W^2

W^2 - W*57in + 756 in^2 = 0

The solutions are given by the Bhaskara's formula:

$W = \frac{57in \pm \sqrt{(-57in)^2 - 4*1*(756in^2)} }{2*1} = \frac{57in \pm 15in}{2}$

Then the two possible values of the width will be:

W = (57in + 15in)/2 = 36 in

W = (57in - 15in)/2 = 21 in

Suppose that we choose the second solution, W = 21in

Now using the equation 57in - W = L we can find the value of L

L = 57in - W = 57in - 21in = 36in

L = 36in

Then we found that the tile has a length of 36 inches and a width of 21 inches.

If you want to learn more, you can read:

brainly.com/question/11137975

4 0

3 years ago

I will mark a thanks and give 10 points please answer

gayaneshka [121]

Answer:

D

Step-by-step explanation:

because it is not a linear equation

4 0

3 years ago