Question

Simplify 48 - 3 x squared over x squared +x-20

Answer 1

48- $\sqrt{3x}/ \sqrt{x} +x-20$ 

x+28-$\sqrt{3}$ Answer

Answer 2

$\frac{48-3x^2}{x^2+x-20}$
remember difference of 2 perfect squares,
a^2-b^2=(a+b)(a-b)
factor them to find ones

48-3x^2=3(16-x^2)=(3)(4+x)(4-x)

x^2+1x-20
find what 2 numbers multiply to -20 and add to 1
-4 and 5
(x-4)(x+5)

now we have
$\frac{(3)(4-x)(4+x)}{(x-4)(x+5)}$
we can clear that (x-4) by force undistributing a negative 1 from that (4-x)
(4-x)=(-1)(x-4)
$\frac{(3)(-1)(x-4)(4+x)}{(x-4)(x+5)}$=
$\frac{(3)(-1)(4+x)}{(x+5)}$=
$\frac{(-3)(4+x)}{(x+5)}$=
$\frac{(-12-3x)}{(x+5)}$