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Elanso [62]
3 years ago
13

Help please !!

Mathematics
2 answers:
Rama09 [41]3 years ago
4 0
Answer: 4.47 units

Explanation:

V(-2,2) and W(-4,-2)

\textnormal{length = } \sqrt{(2 + 2)^2 + (-2 + 4)^2}  =  \sqrt{16 + 4} = \sqrt{20} = 4.47 \textnormal { units}
Andrej [43]3 years ago
4 0
The answer is:  " 4.47 units " .
________________________________________________________
Explanation:
________________________________________________________
Note the Pythagorean theorem for right triangles:

→ a² + b² = c² ; 

Solve for the "positive value of "c" ; 

in which "c" is the "hypotenuse" ; which is the length of <em>VW</em> ; 
_______________________________________
in which one side of a right triangle is from:
 _______________________________________
"Point W" {coordinate of "(-4, -2)" to "(-2, -2)" ; which is "2 units" long; 
_______________________________________
and another side of the right triangle is from:
_______________________________________
  "(-2, -2)" to "(2, 2)" ; which is:  "4 units long)

c² = 2² + 4² ; 

Solve for the "positive value" of "c" ;  which is the "hypotenuse" ; which is the length of <em>VW</em> .
_______________________________________________________

c² = 4 + 16 = 20 ; 

c² = 20 ; 

Take the "positive square root" of each side of the equation; to solve for "c" ; 

 ⁺√(c²) = ⁺√20; 

to get: 

→  c = √4√5 = " 2√5 units " ; 

or; using calculator:  " √20 = 4.4721359549995794 " ;  

→ round to:  "4.47 units" .
_______________________________________________________
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