It's kind of important to know how long it's been since her last cut but...
y=years
6y+4=10
I think that would work.
Answer: I think it might be 2.
Answer: Multiply numerator and denominator by a radical that will get rid of the radical in the denominator. .
Make sure all radicals are simplified. Simplify the fraction if needed.
Step-by-step explanation:
x² + 9x + 1
let's start by grouping the ones with the same variable
(x² + 9x) + 1
(x² + 9x + [?]²) + 1
so, we seem to be missing a value there, to get a perfect square trinomial, let's recall a perfect square trinomial has a middle term that is 2 * "other two values", namely

so, the middle term on this group will be 9x.
we know 2*x*[?] = 9x, so then

so that's our mystery felllow.
now, let's bear in mind that we'll be borrowing from our very good friend Mr Zero, 0, so if we add (9/2)², we also have to subtract (9/2)².
![\bf \left[x^2+9x+\left( \cfrac{9}{2} \right)^2 - \left( \cfrac{9}{2} \right)^2 \right]+1\implies \left[x^2+9x+\left( \cfrac{9}{2} \right)^2 \right]+1- \left( \cfrac{9}{2} \right)^2 \\\\\\ \left( x+\cfrac{9}{2} \right)^2+1-\cfrac{81}{4}\implies \left( x+\cfrac{9}{2} \right)^2-\cfrac{77}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5Bx%5E2%2B9x%2B%5Cleft%28%20%5Ccfrac%7B9%7D%7B2%7D%20%5Cright%29%5E2%20-%20%5Cleft%28%20%5Ccfrac%7B9%7D%7B2%7D%20%5Cright%29%5E2%20%5Cright%5D%2B1%5Cimplies%20%5Cleft%5Bx%5E2%2B9x%2B%5Cleft%28%20%5Ccfrac%7B9%7D%7B2%7D%20%5Cright%29%5E2%20%5Cright%5D%2B1-%20%5Cleft%28%20%5Ccfrac%7B9%7D%7B2%7D%20%5Cright%29%5E2%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%20x%2B%5Ccfrac%7B9%7D%7B2%7D%20%5Cright%29%5E2%2B1-%5Ccfrac%7B81%7D%7B4%7D%5Cimplies%20%5Cleft%28%20x%2B%5Ccfrac%7B9%7D%7B2%7D%20%5Cright%29%5E2-%5Ccfrac%7B77%7D%7B4%7D)