Let us say that y = vertical height and z =
hypotenuse <span>
dz/dt = 600
dy/dt = 0 since y (altitude) is constant
sin(θ) = 2/3
Calculating for the angle: θ = arcsin(2/3) = 0.729728 radians
sin(θ) = y/z
z sin(θ) = y
<span>We then differentiate the two sides with respect to time t:
dz/dt sin(θ)+ z cos(θ) dθ/dt = dy/dt
(600) (2/3) + (3) cos (0.729728) dθ/dt = 0
400 + [3 / cos (0.729728) ] dθ/dt = 0
400+ 4.0249 dθ/dt = 0
dθ/dt = -98.38 radians/hour
= -99.38/60 radians / min
= -1.66 radians / min = 2PI - 1.66 radians / min
<span>= 4.62 radians / min (ANSWER)</span></span></span>
Answer:
1/2
Step-by-step explanation:
1/2 simply because when long division is used to convert it in decimal, it is gonna be the largset
Answer:
LCM = 2^4 x 5^1 x 7^1 = 560
Step-by-step explanation:
<h2>I hope this helps you !! </h2>
Answer:
Step-by-step explanation:
![a_{n} =2(2n+1)](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D2%282n%2B1%29)
![a_{n} =1-3n\\](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D1-3n%5C%5C)