Answer:
titutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
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I am assuming that the second equation is
. In that case, the correct answers are (0, -1) and (3, -8).
Answer:
=0.4
Step-by-step explanation:
1/3= 0.33
5/6=0.83
Then: 0.33/0.83 = 0.4
You can also do 6/15 which results from (1*6)=6 and (3*5)=15
The right answer is congruent and complementary because they both are different from each other and different causes
<span>If
Ellen deposited 6 773 dollars in her account and did not withdraw any amount
for 7 years.
Then she will earn this amount.
=> 1% interest rate per year
=> first year = 6 773 x .01 = 67.73
=> 6773 + 67.73 = 6840.73
=> Second year = 6840.76 * .01 = 68.4073
=> 68.4073 + 6840.76 = 6909.1673
=> Third year = 6909.1673 * .01 = 69.09
=> 6909.1673 + 69.09 = 6978.26
=>4th year = 6978.26 * .01 = 69.78
=> 6978.26 + 69.78 = 7004
=> 5th year = 7004 *.01 = 70.04
=> 7004 + 70.04 = 7074.04
=> 6th year = 7074.04 * .01 = 70.74
=> 70.74 + 7074.04 = 7144.78
=> 7th year = 7144.78 *.01 = 74.45
=> 7144.78 + 74.45 = 7216.23</span>
