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Kaylis [27]
2 years ago
7

Which factors affect the gravitational force between objects? Check all that apply

Physics
1 answer:
neonofarm [45]2 years ago
5 0

Answer:distance between objects and the masses of the objects

Explanation:

Gravitational force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of distance apart

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How much force is needed to accelerate a vehicle with a mass of 1000 kg at a rate<br> of 5 m/s2?
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The force needed to accelerate a vehicle with a mass of 1000kg at a rate of 5m/s2 would be 5000
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Uma wants to recreate the discovery of superconductivity. Which describes the materials needed?
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B)a tool to drop temperatures, mercury, an electric current, and a tool to measure resistance

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"18. Milliliter is equivalent to 1 _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
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18 mililiter is equivilent to 0.0047551
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An airplane takes off at an angle of 75° from its starting point. when the plane has traveled a total distance of 600 feet, its
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Draw a right triangle so that its hypotenuse is 600 ft. The adjacent side is below the vertical, and it makes an angle of 75° with the hypotenuse.

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An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th
stepan [7]

Answer:

Number of photons travel through pin hole=6.4*10^{17}

Explanation:

First we will calculate the energy of single photon using below formula:

E=\frac{h*c}{λ}

Where :

h is plank's constant with value 6.626*10^{-34} J.s

c is the speed of light whch is3*10^{8}

λ is the wave length = 532nm

E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}

E=3.73*10^{-19}J

Number of photons emitted per second:

\frac{5J/s}{1 photon/3.73*10^{-19} }

Number of photons emitted per second=1.34*10^{19} photons/s

\frac{A-hole}{A-beam}=\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

\frac{A-hole}{A-beam}=\frac{d-hole^2}{d-beam^2}

\frac{Ahole}{A-beam}=\frac{1.22^2}{5.5^2}

\frac{A-hole}{A-beam}=\frac{144}{3025}

Number of photons travel through pin hole=1.34*10^{19} *\frac{144}{3025}

Number of photons travel through pin hole=6.4*10^{17}

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2 years ago
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