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Paul [167]
3 years ago
6

the velocity of sound in a certain medium is 1000 m/s. If sound wave has a frequency of 500 Hz, the wavelength would be _.

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:2meter

Explanation:

Velocity=1000m/s

Frequency=500Hz

wavelength=velocity ➗ frequency

Wavelength=1000 ➗ 500

Wavelength=2meter

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A jetliner flies at a constant speed covering 467 miles in 3.3 hours. What is the speed of the plane in miles per hour?
stellarik [79]

Answer:

141.152 miles per hour  is the speed of the plane in miles per hour

Explanation:

Speed of plane = Total distance travelled/total time taken -

v = D/t

Substituting the given values in the above equation, we get

v = 467/3.3 miles /hour

v = 141.152 miles per hour

141.152 miles per hour  is the speed of the plane in miles per hour

8 0
3 years ago
What are the uses of nuclear power ? ​
Alona [7]

Answer:

the main reason is electricity

Explanation:

there are many different things nuclear power does that are good and bad.

5 0
3 years ago
A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it
natka813 [3]

Answer:

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Explanation:

The rotated angle is given by:

\theta=\omega0*t+1/2*\alpha*t^2

Since this is a quadratic equation it can be solved using:

x=\frac{-b \± \sqrt{b^2-4*a*c}  }{2*a}

Rewriting our equation:

1/2*\alpha*t^2+\omega0*t-\theta=0

t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Since \sqrt{\omega0^2+2*\theta*\alpha} >\omega0 we discard the negative solution.

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

8 0
3 years ago
An ocean wave has a wavelength of 15 meters and is moving at 2.5 m/s. what is the frequency
Tasya [4]

Answer:

frequency is .167/s for this wave

8 0
3 years ago
Read 2 more answers
A vibrating tuning fork is held over a water column with one end closed and the other open. As the water level is allowed to fal
DiKsa [7]

Answer:

630 Hz.

Explanation:

As we are considering the one end open pipe. So for the sound wave there will be a pressure node at the open end of the tube as at that place the molecules can not move back and forth. However on the closed end there will be a flow node as the water molecules their are moving back and forth. So it will produces the resonance at the positions 1/4, 3/4.......

we can find the wavelength by multiplying the levels distance by 2.

λ = 2 × 0.27 m = 0.54

f = Vs/λ

  = 340/0.54

  = 630 Hz

6 0
3 years ago
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