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omeli [17]
3 years ago
6

Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth. A. 51

.9, 52, 49, 6 B. 52.9, 52, 49, 104 C. 51.9, 53, 49, 6 D. 52, 52.9, 49, 104
Mathematics
1 answer:
DENIUS [597]3 years ago
3 0
The answer is A.

Hope I helped.
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Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
A test is worth 30 points. Multiple-choice questions are worth 7 point and
kumpel [21]

Answer:cvg

Step-by-step explanation:

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3 years ago
The table shows information about the number of sweatshirts sold and money collected at a fundraiser for school athletic program
Murljashka [212]


…………………………………………….not really sure about the last question

6 0
2 years ago
Brian likes to go bird watching along the Harvest Park Trail in a nearby forest preserve. He wants to calculate the area enclose
QveST [7]

The question has missing details

The m<em>issing options are: </em>

<em>A. 188,000 square yards </em>

<em>B. 138,000 square yards </em>

<em>C. 600 square yards </em>

<em>D. 300 square yards</em>

<em>See attachment 1 for the missing diagram</em>

Answer:

<em>B. 138,000 square yards </em>

Step-by-step explanation:

The figure can be divided into two shapes (see attachment 2)

From attachment 2,

The dimension of the big rectangle is 1300ft by 800ft

The dimension of the small rectangle is 500ft by 400ft

So, the area is:

Area of the big rectangle added to the area of the small rectangle

i.e.

Area = 1300 * 800 + 500 * 400

Area = 1040000 + 200000

Area = 1240000ft^2

Convert to yd^2 by dividing by 9

Area = 1240000yd^2 /9

Area = 137777.777778\ yd^2

<em>From the list of given options, the closest to the area of the diagram is </em>

<em>B. 138,000 square yards  </em>

<em></em>

8 0
3 years ago
The polynomial of degree 5, P ( x ) , has leading coefficient 1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
pickupchik [31]

Answer:

Step-by-step explanation:

(x-3)(x-3)(x²)(x+2)

(x²-6x+9)(x³+2x²)

x^5+2x^4-6x^4-12x^3+9x^3+18x^2

x^5 - 4x^4 - 3x^3 +18x^2

4 0
3 years ago
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