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3 years ago

5

Tom bought 7 new baseball trading cards to add to his collection. the next day his dog ate half of his collection. there are now

only 25 cards left. how many cards did Tom start with?

1 answer:

SVETLANKA909090 [29]3 years ago

6 0

25x2=50-7=43
Tom started out with 43 baseball trading cards

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Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segmen

Nataly_w [17]

Answer:

C. (-13, -7)

Step-by-step explanation:

The location of a point O(x, y) that divides a line AB with location A $(x_1,y_1)$ and B $(x_2,y_2)$ in the ratio m:n is given by:

$x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1$

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

$x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7$

Therefore the coordinates of point X is at (-13, -7)

6 0

3 years ago

Are my answers correct?

Snezhnost [94]

Answer:

20 is x ≥ 25

Step-by-step explanation:

In number 20 you put x is less than or equal to 25 ( x ≤ 25 )

It should be x is greater than or equal to 25 ( x ≥ 25 ) because it says it cannot be less than 25.

All your other answers are correct. Good job.

7 0

3 years ago

Write the equation of 2 lines passing through the point (2, 14).

jeka94

Answer:

Since, the given solution is (2, 14). Therefore, 7x−y=0. Similarly, another equation can be−x+y=−2+14=12. Similarly, another equation can be−2x−y=−2(2)−14=18.

3 0

3 years ago

If a family has 6 children, in how many ways could the parents have 3 boys and 3 girls?

Jlenok [28]

The parents could have 3 boys and 3 girls in 400 ways

<h3>How to determine the number of ways?</h3>

The given parameters are

Children, n = 6

Boys, r = 3

Girls, r =3

The number of combination is:

$Ways = ^nC_{r1} *^nC_{r2}$

So, we have:

$Ways = ^6C_3 *^6C_3$

Apply the combination formula

$Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}$

This gives

Ways = 400

Hence, the parents could have 3 boys and 3 girls in 400 ways

Read more about combination at:

brainly.com/question/11732255

#SPJ1

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2 years ago

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xenn [34]

Answer:

$\frac{1}{10}$ x $(20x-7x^{2} + 30)$

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2 years ago

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