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2 years ago

How do you determine a function if a relation is a function

Mathematics

1 answer:

ira [324]2 years ago

7 0

Answer:

Hello! A function is easily identified when an x value does not have more than 1 y value. a y value can have as many x values to infinity, but x can only have one y.

Example...

x y

3 5

4 5

1 2

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Will get branliest!!!!!!!

lawyer [7]

Answer:

It has the same domain as the function $f(x)=-\sqrt{-x}$

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand cannot be a negative number

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

Verify each statement

Part 1) It has the same domain as the function $f(x)=-\sqrt{-x}$

The statement is true

The domain of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 2) It has the same range as the function $f(x)=-\sqrt{-x}$

The statement is false

The range of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function $f(x)=-\sqrt{x}$

The statement is false

The domain of the function $f(x)=-\sqrt{x}$ is

the interval ---> [0,∞)

Part 4) It has the same range as the function $f(x)=-\sqrt{x}$

The statement is false

The range of the function $f(x)=-\sqrt{x}$ is

the interval ---> (-∞,0]

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valentina_108 [34]

A)
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Height = 8m
Base = 26-11 m

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b) Find AC by using AB as Height and BC as base
AC^2 = AB ^2 + BC ^2

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Firlakuza [10]

Answer:

x=0

Step-by-step explanation:

solve for x by simplifying both sides of the equation then isolating the variable

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