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Natasha_Volkova [10]
2 years ago
8

How do you determine a function if a relation is a function ​

Mathematics
1 answer:
ira [324]2 years ago
7 0

Answer:

Hello! A function is easily identified when an x value does not have more than 1 y value. a y value can have as many x values to infinity, but x can only have one y.

Example...

x                       y

3                       5

4                       5

1                        2

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−7/8 −(−5/6) ​ in simplest form
svp [43]

Answer:

-1/24

Step-by-step explanation:

-7/8 - (-5/6)

Subtracting a negative is like adding

-7/8 + 5/6

Get a common denominator

-7/8 * 6/6    + 5/6 *8/8

-42/48 + 40/46

-2/48

-1/24

3 0
3 years ago
Two equivalent fractions for 37 over 50
stiks02 [169]

Answer:

37/50=74/100

Step-by-step explanation:

8 0
3 years ago
Which expression has the same value as the one below?
9966 [12]

Which expression has the same value as the one below?

i dont kown cause i cant see the choices

7 0
3 years ago
Lucio quiere repartir su colección de estampillas entre la mayor cantidad de amigos pero de manera que todos reciban la misma ca
Daniel [21]

Answer:

Lucio podrá armar 5 grupos iguales de estampillas.

Step-by-step explanation:

El problema plantea un caso de distribución mediante la aplicación del divisor común mayor a todos los números involucrados. Para ello, primero debemos analizar los divisores de cada uno de estos números:

-30: divisible por 2, 3, 5, 6, 10, 15 y 30.

-75: divisible por 3, 5, 15, 25 y 75.

-160: divisible por 2, 4, 5, 8, 10, 16, 20, 32, 40, 80 y 160.

Así, podemos ver que el divisor común mayor a los tres números es 5, ya que 30, 75 y 160 dan como resultado un número entero tras ser divididos por 5.

Entonces, para poder repartir equitativamente sus estampillas entre la mayor cantidad de amigos posibles, deberá repartir 6 estampillas de animales, 15 estampillas de flores y 32 estampillas de ciudades a 5 amigos. De esta manera, Lucio podrá armar 5 grupos iguales de estampillas.

4 0
3 years ago
Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?
nydimaria [60]

Answer:

Any equation of the line that is different from y=x is the solution to the problem.

Step-by-step explanation:

step 1

Find the slope of the line that passes through the points (1, 1) and (5, 5)

m=(5-1)/(5-1)=1

step 2

Find the equation of the line into slope point form

y-y1=m(x-x1)

we have m=1

(x1,y1)=(1,1)

substitute

y-1=(1)(x-1)

y=x-1+1

y=x

therefore

Any equation of the line that is different from y=x is the solution to the problem.

5 0
3 years ago
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