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Digiron [165]
3 years ago
5

In the number 8,888.888, how does the 8 in the hundredths place compare to the 8 in the place to its left? A. The 8 in the hundr

edths place represents of what the 8 to its left represents. B. The 8 in the hundredths place represents of what the 8 to its left represents. C. The 8 in the hundredths place represents 100 times what the 8 to its left represents. D. The 8 in the hundredths place represents 10 times what the 8 to its left represents.
Mathematics
2 answers:
prohojiy [21]3 years ago
4 0
The answer is to the question is D.


AnnyKZ [126]3 years ago
3 0

Answer: The 8 in the hundredths place represents 1/10 of the 8 to its lefts response

Step-by-step explanation:

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Which expressions are equivalent to 7 (negative three-fourths x minus 3)? Select two options.
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<em><u>The equivalent expressions are:</u></em>

7(-\frac{3}{4}x - 3) = (7 \times \frac{-3}{4}x) + (7 \times -3)\\\\7(-\frac{3}{4}x - 3) = \frac{-21x}{4} - 21

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

7(-\frac{3}{4}x - 3)

We have to find the equivalent expressions

By distributive property,

a(b + c) = ab + ac

Therefore,

7(-\frac{3}{4}x - 3) = (7 \times \frac{-3}{4}x) + (7 \times -3)\\\\7(-\frac{3}{4}x - 3) = \frac{-21x}{4} - 21

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The simplified answer is 27m^2

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2 years ago
A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

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