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4 years ago

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Please help asap 25 points

1 answer:

Vikentia [17]4 years ago

7 0

The boundary line is solid and the area above the line is shaded making the inequality

D. y≥3x+2

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Please answer both with work,please use a paper and picture, thanks

Irina-Kira [14]

Answer:

a. $\frac{\textbf{17}}{\textbf{4}}$

b. $\frac{\textbf{3}}{\textbf{8}}$

Step-by-step explanation:

a. $\textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}}$

A mixed fraction of the form $a\frac{x}{y} = a + \frac{x}{y}$

$\therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4}$

$= 4 + \frac{1}{4}$

$= \frac{\textbf{17}}{\textbf{4}}$

b. $\textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}}$

A mixed fraction of the form $-c\frac{a}{b} = - c - \frac{a}{b}$

$\therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8}$

$= 1 - \frac{5}{8}$

$= \frac{8 - 5}{8}$

$= \frac{\textbf{3}}{\textbf{8}}$

Hence, the answer.

8 0

3 years ago

Help please bad please

Sergio [31]

Answer:

$\displaystyle A .20$

Step-by-step explanation:

<u>By </u><u>tangent</u><u> </u><u>theorem</u><u> </u>we acquire:

$\displaystyle x + 10 = 9 + 21$

simplify addition:

$\displaystyle x + 10 = 30$

cancel 10 from both sides:

$\displaystyle x = 20$

hence,

our answer is A

4 0

3 years ago

The coordinates of point Y is (-10,5). The midpoint of XY is (3,-5). Find the coordinates of point X

serg [7]

Answer:

the way its set up its kind of confusing ↑

Step-by-step explanation:

4 0

3 years ago

Understanding how a budget is created will help you develop good financial decision making skills. This is known as: Question 3

Andreas93 [3]

Answer:

True mate

Step-by-step explanation:

3 0

3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0

3 years ago