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pshichka [43]
2 years ago
9

Which of the following expressions is equivalent to 14xy – 28x – 36y + 48? 2(7x – 6)(y – 2)(3y + 4) 2(7x – 6)(y – 2)(3y – 4) 2[7

x(y – 2) – 6(3y – 4)] 2[7x(y – 2) – 6(3y + 4)]
Mathematics
1 answer:
Zolol [24]2 years ago
7 0

The expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

<h3>Factorizing expressions</h3>

Factorization is a way of separating the equations into two separate factors.

Given the expression below;

14xy – 28x – 36y + 48

Group

(14xy – 28x) – (36y + 48)

14x(y - 2) - 12(3y-4)

Factor out the value of 2 from both terms

2[7x(y-2)-6(3y-4)]

Hence the expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

Learn more on factorization here: brainly.com/question/25829061

#SPJ1

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