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3 years ago

Please help, 20 points. Perimeter :)

Mathematics

1 answer:

djyliett [7]3 years ago

8 0

Answer:

Step-by-step explanation:

<em>Look at the picture.</em>

The dimensions of the picture:

(42 - 2x)in × (32 -2x)in

The formula of an area of a rectangle:

A = l · w

l - length, w - width

Substitute l = (42 - 2x), w = (32 - 2x) and A = 900

(42 - 2x)(32 - 2x) = 900

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X=3y-4<br> 2x-y=7<br> use substitution method. pls explain :)

Nesterboy [21]

Answer:

the sustitucion metod is easy x=5 y=3

Step-by-step explanation:

x-3y=-4 (-2)

2x-y=7 (1)

-2x+6y=8

2x-y=7

5y=15

y=3

2x-3=7

2x=10

x=5

4 0

3 years ago

Read 2 more answers

A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),

lana [24]

Answer:

(9) $\frac{1}{12}$ (10) $\frac{1}{12}$ (11) $\frac{5}{12}$ (12) $\frac{1}{4}$ (13) $\frac{1}{6}$ 14) $\frac{5}{36}$ (15) $\frac{1}{12}$ (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are: (3, 6), (4, 5), (5, 4)

$P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}$

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are: (1, 3),(2, 2),(3, 1),

$P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}$

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (4, 1), (4, 2), (5, 1)

$P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}$

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

$P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}$

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4), (5, 5), (6, 6)

$P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}$

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

$P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}$

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

$P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}$

16.Probability of getting two numbers with a sum of 14.

$P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0$

4 0

4 years ago

Find the minimum point for the function f(x) = |2x - 1| (0, ½) (½, 0) (0, -½) (-½, 0)

torisob [31]

Minimum point of an absolute value function is when f(x) = 0
0 = <span>|2x - 1|
2x</span> - 1 = 0
2x = 1
x = 1/2

Minimum point is (1/2, 0)

6 0

3 years ago

BRAINLIEST HELP.............

Rus_ich [418]

I think the answer should be b, since y=3 when x=0, according to the option B.

y = x + 3, B

3 0

3 years ago

Set up a triple integral in spherical coordinates to compute the volume of the region inside the sphere x² + y² + z² = 4 and abo

Mademuasel [1]

The plane meets the sphere in the cylinder

$z=1 \implies x^2+y^2+1^2 = 4 \implies x^2+y^2 = 3 = \left(\sqrt3\right)^2$

In spherical coordinates, the plane has equation

$z = \rho\cos(\phi) = 1 \implies \rho = \sec(\phi)$

and since

$\begin{cases}x = \rho\cos(\theta)\sin(\phi) \\ y=\rho\sin(\theta)\sin(\phi)\end{cases} \implies x^2+y^2 = \rho^2 \sin^2(\phi)$

the cylinder has equation

$\rho^2 \sin^2(\phi) = 3 \implies \rho = \sqrt3 \, \csc(\phi)$

The plane and cylinder thus meet when

$\sec(\phi) = \sqrt3\,\csc(\phi) \implies \tan(\phi) = \sqrt3 \implies \phi = \dfrac\pi3$

So, the volume of the region is given by

$\displaystyle \boxed{\int_0^{2\pi} \int_0^{\pi/3} \int_{\sec(\phi)}^2 \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta}$

7 0

2 years ago