Question

Point O is the center of the circle. What is the value of x?

Answer 1

OQ = 8 + 9 = 17
x^2 = 17^2 - 8^2
x^2 = 289 - 64
x^2 = 225
x = 15

Answer 2

Answer:

x  = 15 cm.

Step-by-step explanation:

Given :Point O is the center of the circle.

To find : What is the value of x?

Solution : We have given that a circle of radius 8 cm .

The tangent to a circle is perpendicular to the radius at the point of tangency.

By applying the Pythagorean theorem

OQ² = OP² + PQ²

Plugging the values  OQ = 9 +8 , OP = 8 , PQ = x

(17)² = (8)² + (x)².

289 =  64 + (x)².

On subtracting 64 from both sides

289 -64 =  (x)²

225 = (x)²

On taking square root both side  

x = 15

Therefore, x = 15 cm.