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Anvisha [2.4K]
3 years ago
12

Help please asap :))))))

Mathematics
2 answers:
Alla [95]3 years ago
4 0
I honestly don’t know but I’m on the same question let me know if you find the answer
ollegr [7]3 years ago
3 0

Answer:

The scale factor is 4

Step-by-step explanation:

Divide one of the sides on the larger shape with the corresponding side on the smaller shape. So if you choose the top one you would to 40/10 which is 4.

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If f and g are continuous functions with f(0) = 2 and the following limit, find g(0). lim_(x->0)[2 f(x) - g(x)] = -3
ladessa [460]

We have by distributivity of limits over sums, and continuity of f(x) and g(x), that

\displaystyle \lim_{x\to0} \bigg(2f(x) - g(x)\bigg) = 2 \lim_{x\to0} f(x) - \lim_{x\to0} g(x) = 2 f(0) - g(0)

Given f(0)=2, it follows that

2^2 - g(0) = -3 \implies g(0) = \boxed{7}

5 0
1 year ago
Given a right cone with base area b and height h what is the formula for the voluime
TEA [102]
Probably, the formula of Volume for a cone of height 'h' and base area 'b' is :

\frac{1}{3}bh
8 0
3 years ago
Read 2 more answers
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
What kind of function is 3y-2=x+7
Phoenix [80]
I agree with the answer above
4 0
3 years ago
The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad 
\begin{cases}
v=\textit{linear velocity}\\
r=radius\\
w=\textit{angular velocity}\\
----------\\
r=18in\\
w=1302\frac{\pi }{min}
\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}
\\\\\\
v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
2 years ago
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