Answer:
Option 4, 64 cm^2
Step-by-step explanation:
The polygon in the shape of a star can be made to be easier to find the area of by cutting it into triangle. For all the "point edges" of the star, we can cut them in half from the vertex to create two right-angled triangles at each edge.
The formula of the area of a triangle is bh/2: the height is given as 6cm, the base is 4cm /2 (after you cut it in half) and so is 2 cm. Since the edges can be cut into two, there are 8 right angled triangles at the edges in total.
To find the area of them:
A=8(bh/2)=8(2*6/2)=48 cm^2
However, we are still missing the part at the centre we haven't found the area of, the square. The area of a square is given by the square of the side length(4cm). Thus, A=4*4=16cm^2
Adding the areas of all the edges and the square:
48 + 16 = 64cm^2
Hence, the area of the polygon is 64cm^2
The required value after simplification of the s = -16/3. None of these are correct.
Given that,
To simplify
and to find the value of s in
.
<h3>What is simplification?</h3>
The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.
Simplification,
![=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7Bx%5E%7B2%2F3%7Dx%5E%7B-1%2F2%7D%7D%7Bx%5Csqrt%7Bx%5E3%7D%5Csqrt%5B3%5D%7Bx%7D%7D%5D%5E2%5C%5C%3D%20%5Cfrac%7Bx%5E%7B4%2F3%7Dx%5E%7B-1%7D%7D%7Bx%5E2x%5E3%2A%7Bx%7D%5E%7B2%2F3%7D%7D%5C%5C%3D%20%5Cfrac%7Bx%5E%7B1%2F3%7D%7D%7Bx%5E%7B17%2F3%7D%7D%5C%5C%3Dx%5E%7B-16%2F3%7D)
Comparing with 
s = -16/3
Thus, the required value of the s = -16/3. None of these are correct.
Learn more about simplification here: brainly.com/question/12501526
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The interquartile range of the data set is 30.
Answer:
The answer is 7.
Step-by-step explanation:
You have to substitute the value of x into the function :





If you visualize the problem, there are two concentric circles, the pool, and the pool plus the walkway. So, we have to subtract the area of these two concentric circles to find the walkway.
Bigger circle: Pool plus walkway
----------------------------------
diameter = 18 + 4(2) -- this is because there is 2 ft of walkway at each far end
diameter = 26 ft
Area = pi*(26/2)^2
Area = 530.93 ft2
Smaller circle:pool
---------------------
diameter = 18 ft
Area = pi*(8/2)^2
Area = 50.27 ft2
Area of walkway
----------------
A = 530.93 - 50.27
A = 480.66 ft2
Then the cost would be
Cost = $4.25 * 480.66
Cost = $2,042.81