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Maru [420]
3 years ago
10

10x^3+40x^2+15x------------------------------ 5x​

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

Step-by-step explanation:

\dfrac{10x^3 + 40x^2 + 15x}{5x}\\ \dfrac{10x^3}{5x} +\dfrac{40x^2}{5x}+\dfrac{15x}{5x}

2x^2 + 8x + 3 is your final answer.

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The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept.

The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:

m=\frac{y_2-y_1}{x_2-x_1}

From the table, the line passes through the points (4, 8) and (8, 12), then its slope is:

m=\frac{12-8}{8-4}=\frac{4}{4}=1

Substituting with m = 1 and the point (4, 8) into the general equation, we get:

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y = x + 4

b. To graph the line y = x + 4, we need to draw two points and then connect them with a line. Replacing with x = 0 into the equation:

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