Here, the number is = 9/15/18
We can re-write it as: 9 /15*18 = 9/270 = 1/30
In short, Your Answer would be 1/30
Hope this helps!
Answer:
1
Step-by-step explanation:
Answer:
Step-by-step explanation:
bc²-2a/b=6(3)²-2×12/6=54-4=50
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
No singular point due to the exponent in the solution
The interval is ![-\infty](https://tex.z-dn.net/?f=-%5Cinfty%20%20%3C0%20%3C%20%20%5Cinfty)
b
NONE
Step-by-step explanation:
From the question we are told that
![\frac{dy}{dx} = 9y](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20%209y)
The generally solution is mathematically represented as
![\frac{dy }{dx} = 9y](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%20%7D%7Bdx%7D%20%20%3D%20%209y)
=> ![\frac{dy}{y} = 9dx](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7By%7D%20%20%3D%20%209dx)
integrating both sides
![\int\limits {\frac{ dy}{y} } \, = \int\limits {9} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%20%20%7B%5Cfrac%7B%20dy%7D%7By%7D%20%7D%20%5C%2C%20%20%3D%20%5Cint%5Climits%20%20%7B9%7D%20%5C%2C%20dx)
=> ![lny = 9x + c](https://tex.z-dn.net/?f=lny%20%3D%209x%20%2B%20c)
=> ![y = e^{9x +c }](https://tex.z-dn.net/?f=y%20%3D%20%20e%5E%7B9x%20%2Bc%20%7D)
=> ![y = e^{9x} e^{c}](https://tex.z-dn.net/?f=y%20%3D%20%20e%5E%7B9x%7D%20e%5E%7Bc%7D)
Here ![e^c = C](https://tex.z-dn.net/?f=e%5Ec%20%20%3D%20%20C)
=> ![y = C e^{9x}](https://tex.z-dn.net/?f=y%20%3D%20C%20%20e%5E%7B9x%7D)
From the above equation we see that the domain for x has no singular point the interval is
![-\infty](https://tex.z-dn.net/?f=-%5Cinfty%20%20%3C0%20%3C%20%20%5Cinfty)
Also there is no transient term in the general solution obtained because as
there no case where ![y \to 0](https://tex.z-dn.net/?f=y%20%5Cto%200)
Answer:
very good
Step-by-step explanation:
very good