Off topic, I like your username :] good luck with whomever answers though <33
Answer: 0.002718
Step-by-step explanation:
Given : The population mean annual salary for environmental compliance specialists is about $62,000.
i.e.
Sample size : n= 32

Let x be the random variable that represents the annual salary for environmental compliance specialists.
Using formula
, the z-value corresponds to x= 59000 will be :

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than $59,000 :-

Hence, the probability that the mean salary of the sample is less than $59,000= 0.002718
Answer:
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Step-by-step explanation:
Total no. of students - 140 students
Total no. of students from all schools= 140+70+35+105=350
school A= 140÷350×100=40./. (multiplying by 100 because it's the total percentage )
School B = 70÷350×100=20./.
School C = 105÷350×100=30./.
School D = 105÷350×100= 10./.
Consisting all the schools percentage it gives 100./.
Hope this helps