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Nitella [24]
2 years ago
9

C bottom left ybkyktfvtfjrddkud

Mathematics
1 answer:
cricket20 [7]2 years ago
7 0

Answer:

hdisiejehe

Step-by-step explanation:

step sister

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There are 45 rose bushes currently in the park. Park workers will plant more rose bushes today. When the workers are finished th
stepan [7]

Answer:

9 rose bushes have been planted

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3 years ago
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a dvd has a diameter of 16 centimeters.what is the the area of the dvd?round the answer to the nearest hundredth.use 3.14 for n
melomori [17]

Answer:

A = 201 cm²

Step-by-step explanation:

We know that the area of a circle can be calculated with the formula:

A = πr² = π(d/2)²

with d being the diameter.

Therefore:

A = 3.14(8cm)² = 201 cm²

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2 years ago
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Please help!!!!!!!!!!!!!!!!!!!!!!!!!! answer both
weeeeeb [17]

<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>

Given expression ,

\implies 13^{\frac{3}{4}}

We know that, a^{\frac{m}{n}} = \sqrt[n]{a^m}

Therefore , this can be written as ,

\implies \sqrt[4]{13^3}

<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>

Given expression ,

\implies \sqrt[3]{24^{10}}

We know that,a^{\frac{m}{n}} = \sqrt[n]{a^m}

Therefore, this can be written as ,

\implies 24^{\frac{10}{3}}

5 0
2 years ago
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Will give brainliest PLEASE HELP!!! :D
marshall27 [118]

Answer:

a

Step-by-step explanation:

hope this helps

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5 0
3 years ago
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Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a
Sladkaya [172]

Answer:

y=(\ln{x})^2

point of extremity: (1,0)

vertical asymptote: along the y-axis (x = 0)

point of inflection: (e,1)

Solution:

Although all these points can be directly observed from the graph below, but these are the analytical solutions if you're curious!

1) Extreme point can be found by differentiating 'y' once and equating to zero. solving for x:

\dfrac{dy}{dx}=\dfrac{dy}{dx}((\ln{x})^2)

\dfrac{dy}{dx}=2\ln{x}\left(\dfrac{1}{x}\right)

substitute dy/dx = 0, and solve for x

0=2\ln{x}\left(\dfrac{1}{x}\right)

0=2\ln{x}

x=e^0

x=1

use this value of x back in y, to find the y-coordinate of the extreme point

y=(\ln{1})^2

y=0

The extreme point = (1,0)

2) Differentiate y twice to find the inflection point.

\dfrac{dy}{dx}=2\ln{x}\left(\dfrac{1}{x}\right)

\dfrac{d^2y}{dx^2}=2\ln{x}\left(-\dfrac{1}{x^2}\right)+\left(\dfrac{1}{x}\right)\left(\dfrac{2}{x}\right)

\dfrac{d^2y}{dx^2}=\dfrac{2}{x^2}\left(-\ln{x}+1}\right)

substitute d2y/dx2 = 0, and solve for x

0=\dfrac{2}{x^2}\left(-\ln{x}+1}\right)

0=-\ln{x}+1

\ln{x}=1

x = e

use this value of x back in y, to find the y-coordinate of the inflection point

y=(\ln{e})^2

y=1

The extreme point = (e,1)

6 0
3 years ago
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