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ASHA 777 [7]
3 years ago
12

From 75 pencils to 225 penicls

Mathematics
1 answer:
Masja [62]3 years ago
3 0

Answer:

He gained 150 pencils

Step-by-step explanation:

So this person had 75 pencils and now has 225?

If so, this is just a subtraction problem!

Steps:

1. 225-75=150

--Subtract how many pencils he had from how many he has now to see how much he gained

This person gained 150 pencils.

Hope this helped!! :)

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Did I get this right?
natima [27]

Answer: Yes, the answer is 40 quarters.


Step-by-step explanation:

1. You need to remember that 4 quarters make a dollar.

2. Keeping this on mind, you can make a Rule of three, as following: If there are 4 quarters in 1 dollar, how many quarters are in 10 dollars?

Then:

4 quarters-------1 dollar

          x---10 dollars

x=\frac{(10dollars)(4quarters)}{1dollar}\\x=40quarters

3. Therefore, there are 40 quarters in one roll.


7 0
3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
3 years ago
Let $f(x) = 12x^9 + x$. Find $f(3) + f(-3)$.
BlackZzzverrR [31]

Answer:

Ok, here goes:  f(3) means take f(x) and plug in 3 wherever we see x.  So

f(3) = 12*39 + 3 = 236196 + 3

f(3) = 236199

Likewise, f(-3) means take f(x) and plug in (-3) wherever we see x.  So

f(-3) = 12*(-3)9 + (-3) = -236196 - 3

f(-3) = -236199

Putting those two things together, we get

f(3) + f(-3) = 236199 - 236199 = 0

Step-by-step explanation:

7 0
1 year ago
There are 10 marbles in the bag below. 7 of the marbles are red, 1 is purple and 2 are green. A marble is picked at random from
zepelin [54]

Answer:  a) 0.7

               b)  70%

Step-by-step explanation:

a) There are 10 marbles.The red marbles are 7

                so that  7/10

                 then change to decimal 7/10=0.7

b) if we get percentage *100

        so,    7÷10*100%

                 70%                            

7 0
2 years ago
Can someone please help me on this problem
Dafna1 [17]

Answer:

Step-by-step explanation:

Perimeter is all sides added together.

l is length, w is width, and P is perimeter.

2l + 2w = P\\2(5x) + 2(x - 3) = 42\\10x + 2x - 6 = 42\\12x - 6 = 42\\12x = 48\\x = 4

5 0
3 years ago
Read 2 more answers
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