Hello,

In details:
s= 1 +3 +5+7+9+.... +2(k-2)+1 +2(k-1)+1
s= 2(k-1)+1 +2(k-2)+1 +.... +9+7+5 +3 +1
2s=(2k-2+2) +(2k-4+4)+...........................................+(2k-2+2)
=2k+2k+2k+....+2k (there is k terms)
2s=2k*k
2s=2k²
s=k²
Answer J
Answer:
9/4
Step-by-step explanation:
You multiply 3/8 by 6.
Part (i)
I'll use H in place of T to represent the heat of the object. That way there isn't a clash of variables lowercase t vs uppercase T.
The equation we're working with is updated to:
H(t) = 22 + a*2^(bt)
Plugging in t = 0 as the initial time value should lead to the temperature being H = 86 degrees Celsius.
So,
H(t) = 22 + a*2^(bt)
86 = 22 + a*2^(b*0)
86 = 22 + a*2^0
86 = 22 + a*1
86 = 22 + a
a+22 = 86
a = 86-22
a = 64
<h3>Answer: 64</h3>
=====================================================
Part (ii)
We'll use the value of 'a' we found earlier. Plus we'll use the fact that H = 28 when t = 0.5 (since 30 min = 30/60 = 0.5 hr).
H(t) = 22 + a*2^(bt)
28 = 22 + 64*2^(b*0.5)
28-22 = 64*2^(0.5b)
64*2^(0.5b) = 6
2^6*2^(0.5b) = 6
2^(6+0.5b) = 6
log( 2^(6+0.5b) ) = log(6)
(6+0.5b)*log(2) = log(6)
6+0.5b = log(6)/log(2)
6+0.5b = 2.5849625
0.5b = 2.5849625-6
0.5b = -3.4150375
b = -3.4150375/(0.5)
b = -6.830075
<h3>Answer: Approximately -6.830075</h3>
Statement given :
→Sara says "If you subtract 11 from my number and multiply the difference by -3 , the result is -54 .
<u>To</u><u> </u><u>f</u><u>ind</u><u> </u>:
SOLUTION :
Let us take Sara's Number be “x”.
★According to Question,
→ x - 11×(-3)= -54
→ x + 33 = -54
→ x = -54-33
→ x = (-87)
let's verify our number,and check whether it's correct or not !
x - 11×(-3)= -54
<u>Putt</u><u>ing</u> <u>the</u> <u>value</u> <u>of</u> <u>x</u>
(-87) - 11 × (-3)= -54
(-87) + 33 = -54
(-54) = -54
Hence, The L.H.S. = R.H.S.
Thus,our number is Verified.
Amount to be paid back = $ 88,624.36
<u>Step-by-step explanation:</u>
Principal amount = $ 40,000
Rate of interest = 7.5%
Number of years = 11

Plugin the values as,



