Answer:
0.666666667
Step-by-step explanation:
Answer:
s = 11
Step-by-step explanation:
Given
= 22 ← substitute r = 242
= 22 ( multiply both sides by s )
242 = 22s ( divide both sides by 22 )
11 = s
Eleven times a number X, minus a second number Y
So, The algebraic equation formed with this data is;
<h3>X×11-Y</h3>
Answee:
We have these two equations:
-2x +4y =-22
2x + 8y -26
We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:
2x + 8y =-26 ---- -2x - 8y =26
Now we have this:
-2x +4y = -22
-2x -8y = 26
Now e substract both equations:
-2x - (-2x) +4y -(-8y) = -22-26
12y = -48
Y = -48/12 = -4
And we replace to get x
-2x + 4y = -22
-2x +4*(-4)=-22
-2x - 16 = -22
x= -6/-2 =3
Answer:
Probability of having at least 4 Girls
= 0.6875
Step-by-step explanation:
Probability of having at least 4 Girls is 1-probability of having exactly 3 girls
Total number of children= 5 = N
Probability of having a girl p = 0.5
Probability of not having a girl q= 0.5
X= 3
Probability of at least 4 girls is given by
Probability= NCX(p)^x(q)^(N-x)
Probability = 5C3(0.5)^3(0.5)^(5-3)
Probability = 5C3(0.5)^3(0.5)^2
Probability= 5!/3!2!(0.5)^3(0.5)^2
Probability= 10(0.125)(0.25)
Probability= 0.3125
Probability of having at least 4 Girls
= 1- 0.3125
= 0.6875
