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Marysya12 [62]
3 years ago
5

I need help on these please ​

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

its the third answer, fifth, and first. Im not sure tho.

Step-by-step explanation:

if it isnt right im so sorry T^T

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2 gross finger puppets; 2 gross bookmarks; 4 gross assorted pencils; 2 gross animal erasers; 2 gross foam craft kits; 2 gross glow in the dark stickers.

This gives 14 gross prizes; 14*144 = 2016.
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This gives enough extra for 27 more bags, in case more people than expected show up.
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The answer is d. it isn’t an exact number
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Find the surface area of the figure below
Ivahew [28]

Answer:

64

Step-by-step explanation:

square= 16

triangle= 12

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Evaluate composite functions
Vlada [557]

Answer:

2

Step-by-step explanation:

Step 1: Write out equation g(f(a))

1/√a

Step 2: Plug in 0.25 for <em>a</em>

1/√0.25

You answer should be 2

5 0
3 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
3 years ago
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