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nasty-shy [4]
3 years ago
13

There are 10 students in a math class. Nine of the students had the following final exam scores: 68% 47% 81% 96% 91% 84% 61% 66%

76% what would the tenth student need to earn on the final exam so that the average final Exam score for all 10 students is 75%?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0
Well since right now the average is 74.4, the tenth student would need to earn an 80 so the team got exactly an average of 75
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Is the number there three? if you answer to me i will give you twenty Points.
juin [17]

Answer:

2

Step-by-step explanation:

3 x 2 = 6

1 x 2 = 2

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7 0
2 years ago
Javier earns $7.50 per hour and works 20 hours per week. He wants to know how many weeks, w, he will need to work to save
disa [49]

Answer:

8 weeks

Step-by-step explanation:

So first you find out how much money he makes per week, by doing 7.5 x 20 you will find that. Now you need to find how many weeks it will take, find this by dividing 1200 by the amount he makes per week and you will end up with 8.

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3 years ago
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What is 6/10 fraction as decimal
dexar [7]
I am pertty sure its 0.6 but if i am wrong sorry
4 0
3 years ago
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What is 10* 3.8 exponent of 6 in scientific notation
Tju [1.3M]
3.8 x 3.8 x 3.8 x 3.8 x 3.8 x 3.8 = 3010.9363843010.936384 x 10 = 30109.36384
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8 0
3 years ago
Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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