Five exterior angles of a hexagon are 41° 32°,67º 71°, and 55°, What is the measure of the sixth exterior
angle
Can yo help me?
Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.

We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.

Hence, the required temperature of the gas is 421.4 K.
The answer is 5.
hope that helps!<span>(○^▽^○)</span>
Answer:
1) 6x-10y=7 2)5x-3y=8
Step-by-step explanation: