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4 years ago

The north part of the kingdom, represented by n(x)=6x^2+x−7, is being divided by a(x)=2x+3.

Mathematics

1 answer:

Sveta_85 [38]4 years ago

7 0

Answer:

The correct answer is,

The quotient is 3x - 4

Step-by-step explanation:

It is given that,

n(x) = 6x^2 + x − 7

a(x) = 2x + 3

To find n(x) by a(x)

n(x) = 6x^2 + x − 7

a(x) = 2x + 3

n(x) by a(x). can be written as,

3x - 4

2x + 3 ) 6x^2 + x − 7

6x^2 + 9x

-8x - 7

-8x - 12

Therefore quotient = 3x - 4

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$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
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\\ \quad \\
f(x)=&{{ A}}\mathbb{R}^{{{ B}}x+{{ C}}}+{{ D}}
\end{array}$ $\bf \begin{array}{llll}
% right side info
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\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}
\end{array}$

$\bf ----------------------------\\
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\\ \quad \\
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\\ \quad \\
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\\ \quad \\
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