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Colt1911 [192]
3 years ago
10

1 of 20 (19 complete)

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

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What happens to the distance between each billiard ball during this rigid<br><br> transformation?
Delicious77 [7]

The question is incomplete. Here is the complete question.

To set up a game of billiards, the first player moves the balls contained within a triangular rack as shown. What happens to the distance between each billiard during this rigid transformation?

A. The distance remains constant throughout the transformation.

B. The distance decreases at the start and increases after all motion stops.

C. The distance stays the same at the start but decreasesexactly when motion ends.

D. The distance increases at the start and then decreases as the rack gets further from the player.

Answer: A. The distance remains constant throughout the transformation.

Step-by-step explanation: In a <u>rigid</u> <u>motion</u>, all moving points in the plane are moving in way such tha:

1)  relative distance between them stays the same and

2) relative position of the points stays the same

There are four types of rigid motions: translation, rotation, reflexion and glide reflection.

<u>Translation</u>: every point or object is moved by the same amount and in the same direction;

<u>Rotation</u>: the object rotates by the same amount around a fixed point;

<u>Reflexion</u>: the object exchange points from one side of a line with points on the other side of the line at the same distance from the line;

<u>Glide</u> <u>Reflection</u>: is a mirror reflection followed by a translation parallel to the mirror.

In the game of billiards, because all the balls are inside the triangular rack, the distance, and also the position, between them stays the same, limited by the rack. Since they are moving by the same amount in the same direction, the rigid transformation is a translation.

Therefore, the distance of the balls in the triangular rack remains constant throughout the transformation.

6 0
3 years ago
Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9
Katena32 [7]

Given :-

  • y varies directly as x, and y=14 when x=4.

To Find :-

  • the value of y when x=9 .

Solution :-

<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>,</u>

  • y = kx ( k is constant )

<u>When</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>,</u>

  • 14 = k(4)
  • k = 14/4
  • k = 7/2

<u>W</u><u>h</u><u>e</u><u>n</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>,</u>

  • y = 7/2*9
  • y = 63/2
  • y = 31.5
8 0
2 years ago
Tesla Pipe Company is creating metal pipe for an underground pipe line. According to the specifications given to them, the insid
Aleks [24]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What would be the least amount of money needed to purchase exactly 19 muffins?
Lady bird [3.3K]
B: 9.25

12/19=5.75/x
X=9.10 but least amount which is 9.25
7 0
2 years ago
Read 2 more answers
1,2,4,7,11,16,22, ___,____<br> What is the rule?
Paha777 [63]
Find rates of change until you find a constant.

dy/dx=1,2,3,4,5,6

d2y/dx2=1,1,1,1,1  

So the acceleration, d2y/d2x, is constant.  This means that this is a quadratic sequence of the form a(n)=an^2+bn+c.  So we can set up a system of equations to solve for the values of a,b, and c.  Using the first three points, (1,1), (2,2), and (3,4) we have:

9a+3b+c=4, 4a+2b+c=2, and a+b+c=1  getting the differences...

5a+b=2 and 3a+b=1  and getting this difference...

2a=1, so a=1/2 making 5a+b=2 become:

2.5+b=2, so b=-1/2, making a+b+c=1 become:

1/2-1/2+c=1, so c=1  so the rule is:

a(n)=0.5x^2-0.5x+1  or if you prefer to not have decimals

a(n)=(x^2-x+2)/2
6 0
3 years ago
Read 2 more answers
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