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EleoNora [17]
3 years ago
9

Tao uses elimination to solve the following system of linear equations. -2x+4y=162x+2y=8Which ordered pair is a solution to the

system?
a. (0, 4)
b. (0, 8)
c. (4, 0)
d. (8, 0)
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

The correct answer is the first option.


If you want to use elimination, you can sum the two equations for example, so that the x's simplify:


(-2x+4y)+(2x+2y) = 16+8


6y = 24


y = 4


Plug this value for y in one of the equations to derive the value of x:


2x+2y=8 \implies 2x + 8 = 8 \implies x = 0


So, the solution is (x,y) = (0,4)

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Answer each part below using only mental math, and describe your method. a. If 39 is 1% of a number, what is that number? How di
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3 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean \mu and standard deviation \sigma, we have these following probabilities

Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827

Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545

Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So \mu = 53, \sigma = 11

So:

Pr(53-11 \leq X \leq 53+11) = 0.6827

Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545

Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973

-----------

Pr(42 \leq X \leq 64) = 0.6827

Pr(31 \leq X \leq 75) = 0.9545

Pr(20 \leq X \leq 86) = 0.9973

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have Pr(31 \leq X \leq 75) = 0.9545 = 0.9545 subtracted by Pr(42 \leq X \leq 64) = 0.6827 is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

P = {0.9545 - 0.6827}{2} = 0.1359

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0
3 years ago
Anne borrowed $600 for 1.5 years. The yearly interest rate was 12%. How much interest did she owe at the end of 1.5 years?
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3 years ago
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