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mart [117]
3 years ago
15

Two bike riders left each other and started to ride in opposite directions. Two hours later they were 54 miles apart. If one of

them averaged twice the average rate of the other, what was the rate of each?
Mathematics
1 answer:
Elis [28]3 years ago
3 0

Answer:

The speed of right going rider is 9 mph

The speed of left going rider is 18 mph

Step-by-step explanation:

Given as :

The total distance apart both the riders = 54 miles

Let The speed of right going rider = x mph

and The speed of left going rider = 2 x  mph

The Distance cover by right going rider = D miles

The Distance cover by left going rider = 54 - D  miles

Total time for both = 2 hours

So, Time = \dfrac{\textrm Distance}{\textrm Speed}

Or ,  Distance = speed × Time

For right going rider

       D = x × 2

For left going rider

      54 - D = 2 x × 2

Or, from first equation

     54 - 2 x = 4 x

or, 54 = 4 x + 2 x

or, 6 x = 54

∴   x = \frac{54}{6}

I.e x = 9 mph

So, The speed of right going rider = 9 mph

and The speed of left going rider = 2 × 9 = 18  mph

Hence The speed of right going rider is 9 mph

and The speed of left going rider is 18 mph   answer

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romanna [79]

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions \frac{40}{8}=\frac{x}{10} and \frac{x}{40}=\frac{10}{8}. We are asked to find why the solutions to our given proportions are equal.

We can solve proportions by cross multiplying them.

After cross multiplying our both proportions we will get same equation that is:

40*10=8*x

400=8x

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8x=400

Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.

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Step-by-step explanation:

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Am I right ? <br> [[ PLEASE HELP IF I"M NOT CORRECT. EXPLAIN, SHOW DETAILS, ETC. ]]
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D 12.57

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Answer:

2/3

Step-by-step explanation:

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