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joja [24]
2 years ago
10

Please help I have 9 more questions I will be posting nd I really need to get this done and I will help in any way I can , thank

you!

Mathematics
1 answer:
VladimirAG [237]2 years ago
5 0
I'm pretty sure the answer would be B, but not entirely sure. I'm rusty on my linear inequalities. It would make sense because if you divide -21 by -7, the sign would flip and make a positive 3 which is the Y intercept.
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Jackson bought 5 ounces of raisins for $4. How much could he have buy for 1$?
Yuliya22 [10]
If you do 5 divide by 4 then you can find what 1$ would be worth so ie.
5 divide by 4 is 1.25 which means that for 1$ you could buy 1.25 ounces
4 0
3 years ago
Read 2 more answers
Find the 97th term of the arithmetic sequence
kozerog [31]
<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1  = 25

The difference between two terms, d = 29 - 25 = 4

To find the 97th term,

By formula, a_{n}  = a_{1} + (n - 1) d

Substituting the values in the above equation, we get

a_{97}  = 25 + (97 - 1) 4

= 25 + (96 * 4)

= 25 + 384

= 409

The 97 th term in the given sequence is 409.

3 0
2 years ago
What is percent change from $18 to 28$? Round to nearest tenth place​
zavuch27 [327]

Answer:

35.2%

Step-by-step explanation:

3 0
3 years ago
A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102
cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

<u>Given:</u>

<em>n</em> = 1000

\hat p = 0.102

z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

6 0
2 years ago
BRAINLIEST <br> Please answer these
miskamm [114]

Answer:

that's my answer in mathematics hope it helps for you

6 0
2 years ago
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