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3 years ago

What are the sides of an angle

2 answers:

7 0

Terminal side of an angle - trigonometry. In trigonometry an angle is usually drawn in what is called the "standard position" as shown on the right<span>. In this position, the vertex (B) of the angle is on the origin, with a fixed side lying at 3 o'clock along the positive x axis.</span>

Serhud [2]3 years ago

6 0

Terminal and Initial sides.

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Simplify the expression by combining like

MatroZZZ [7]

Answer:

Step-by-step explanation:

2m^2-m+4m^2+8m combine like terms

6m^2+7m

3 0

3 years ago

Read 2 more answers

The temperature in Celsius would be,

elena-14-01-66 [18.8K]

First derisive the equation for C

$\\ \sf\longmapsto F=\dfrac{9}{5}C+32$

$\\ \sf\longmapsto C+32=\dfrac{5}{9}F$

$\\ \sf\longmapsto C=\dfrac{5}{9}F-32$

F=101F

$\\ \sf\longmapsto C=\dfrac{5}{9}101-32$

$\\ \sf\longmapsto C=\dfrac{505}{9}-32$

$\\ \sf\longmapsto C=56.1-32$

$\\ \sf\longmapsto C=24.1°C$

8 0

3 years ago

Miss Garner has 69 gold stickers. She wants to give the same number of stickers to each of her 15 students. If she gives away as

Hatshy [7]

Answer: 69/15=4 and remainder 9

Step-by-step explanation: Since 15 x 4 = 60, 15 can't go into 9 so 9 in the leftover

7 0

3 years ago

Read 2 more answers

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

Find the whole quantity if 5 percent of it is 500

liq [111]

Answer:

10,000

Step-by-step explanation:

500/0.05= 10,000

You take the amount you are given divided by the decimal form of the percentage you are given to find the answer. It's a reverse from the way you find 5% of 10,000.

0.05=5%

Check your work: 10,000*5%= 500

5 0

3 years ago