1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alina [70]
2 years ago
13

Jrian"s plane was supposed to leave at 1:25. If he arrived one hour and 52 minutes early, what time did he arrive at the airport

?
Mathematics
2 answers:
Arturiano [62]2 years ago
6 0
11:27

First, 1:25 to 1:00 would be 25 minutes early. Therefore, you do 52 - 25 = 33. One hour and 33 minutes early now. Then, you do one hour before 1:00 which would be 12:00. Finally, you would do 60 - 33 because 12:00 is technically 12:60. 60 - 33 = 27. The answer is 11:27.
marissa [1.9K]2 years ago
6 0
He arrived at 11:33
One hour earlier would be 12:25
52 minus 25 is 27
60 minus 27 is 33
So you get 11:33
You might be interested in
What number multiplied by itself 3 times equals-343
professor190 [17]
343*3=1029 this is the answer 
7 0
2 years ago
What are the zeros of (x-2)(x^-9)
Nostrana [21]
I suspect you may have slipped up as you copied the question. Exactly as you wrote it, it has a single zero, at x= 2 .
8 0
2 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
The Better Nutter Butter Co packed 400 lb. of peanut butter into jars holding 2.5 lbs. each. How many jars were used?
Rus_ich [418]

Answer:

160 jars

Step-by-step explanation:

To find how many jars were used, we just need to divide the amount of stuff by the amount of stuff a jar can hold.

400 (the amount of peanut number in pounds) / 2.5 (the amount of peanut butter each jar can hold) = 160.

So, 160 jars were used to package the 400 pounds of peanut butter.

8 0
2 years ago
Solve this equation<br> 5x+2=3x-20-1x
Rainbow [258]
5x+2=3x-20-1x\\5x+2=2x-20\ \  \ \ |subtract\ 2\ from\ both\ sides\\5x=2x-22\ \ \ \ |subtract\ 2x\ from\ both\ sides\\3x=-22\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=-\frac{22}{3}}\Rightarrow\boxed{x=-7\frac{1}{3}}
6 0
2 years ago
Read 2 more answers
Other questions:
  • The difference of two numbers is 15. The larger number is 1 more than 3 times the smaller number. Find the two numbers.
    7·2 answers
  • The bacteria starts at 2million.The doctor prescribes an antibiotic that reduces the bacteria population to 1/4 of its size each
    14·1 answer
  • How many earths could fit in jupiter math?
    12·2 answers
  • Please help thank you!!
    12·1 answer
  • An apartment has 115 square meters of carpeting. How much is this in square feet? Use the following conversion: 1 square meter i
    13·1 answer
  • The histogram shows the weights, in pounds, of checked luggage on a flight. The median weight of a checked bag is 27.5 pounds. H
    9·1 answer
  • What is the length of the hypotenuse?
    9·1 answer
  • What scale factor can you use to MULTIPLY 10<br> to get to 20?
    14·2 answers
  • Please help this is TIMED!!
    15·2 answers
  • It takes Dimitri 9 minutes to make a simple bracelet and 20 minutes to make a deluxe bracelet. He has been making bracelets for
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!