Answer:
3) 1 5/6 mi
4) a. 4 cm, 6 ft
b. 6.4 cm, 9.6 ft
c. same as part a
Step-by-step explanation:
3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...
4×1/3 + 4×1/8 = 4/3 + 4/8
= 1 1/3 + 1/2 = 1 2/6 + 3/6
= 1 5/6 . . . . . miles
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4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.
a. 8 cm = 4 cm + x
8 cm - 4 cm = x = 4 cm
The distance in the room is ...
(4 cm)×(1.5 ft/cm) = 6 ft
b. 10.3 cm = 3.9 cm + y
10.3 cm - 3.9 cm = y = 6.4 cm
The distance in the room is ...
(6.4 cm)×(1.5 ft/cm) = 9.6 ft
c. The answer to part b was obtained in the same way as the answer to part a. The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.
Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:
Rewrite the integrand:
The integral is then
Answer: she is jogging 2.25 i think
Step-by-step explanation:
im sorry im not sure i just divided 135 by 60 but i dont think its right:(
