Answer:
See below
Step-by-step explanation:
If an expression is not dependent on x, it simplified form must not contain x. To show that this is the case for (a) and (b) we need to simplify them and assess:
(a)
![(x-5)(x+8)-(x+4)(x-1)=\\=x^2-5x+8x-40-x^2-4x+x+4=-36](https://tex.z-dn.net/?f=%28x-5%29%28x%2B8%29-%28x%2B4%29%28x-1%29%3D%5C%5C%3Dx%5E2-5x%2B8x-40-x%5E2-4x%2Bx%2B4%3D-36)
Indeed, does not depend on x!
And (b)
![x^4-(x^2-1)(x^2+1)=x^4-x^4+x^2-x^2+1=1](https://tex.z-dn.net/?f=x%5E4-%28x%5E2-1%29%28x%5E2%2B1%29%3Dx%5E4-x%5E4%2Bx%5E2-x%5E2%2B1%3D1)
Again, does not depend on x.
$25! :)
Good luck! I’d appreciate if you made this the brainliest answer! :)
Answer:
![\boxed {\boxed {\sf D. \ f(3)= 30}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20D.%20%5C%20f%283%29%3D%2030%7D%7D)
Step-by-step explanation:
We are given the function:
![f(x)= 3(2)^x+6](https://tex.z-dn.net/?f=f%28x%29%3D%203%282%29%5Ex%2B6)
We want to find f(3), so we must substitute 3 in for x.
![f(3)= 3(2)^3+6](https://tex.z-dn.net/?f=f%283%29%3D%203%282%29%5E3%2B6)
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.
Solve the exponent first.
![f(3)= 3(8)+6](https://tex.z-dn.net/?f=f%283%29%3D%203%288%29%2B6)
Multiply 8 and 3.
![f(3)= 24+6](https://tex.z-dn.net/?f=f%283%29%3D%2024%2B6)
Add.
![f(3)=30](https://tex.z-dn.net/?f=f%283%29%3D30)
For the function given, f(3) is 30.
Answer: Its the first one
You draw the graph of the line y=3x+5
but make the line dotted.
Label the line y>3x+5
Note that if instead we hade y≥3x+5 the line would be solid.
If you draw a line parallel to the y-axis through any x-value the value of y can be any on that vertical line that is above but not on the line y=3x+5
. So you end up with a 'feasible' region of solutions for y