Question

Given a mean of 61.2 and a standard deviation of 21.4 what is the z score of the value 90 rounded to the nearest tenth?

Answer 1

Answer:

The z-score of 90 is 1.35

Step-by-step explanation:

The z-score is calculated using the formula:

$z = \frac{x - \mu}{ \sigma}$

From the question, it was given that the mean is

$\mu = 61.2$

and the standard deviation is

$\sigma = 21.4$

and x=90.

We substitute the given values to obtain:

$z = \frac{90 - 61.2}{21.4}$

$z = \frac{28.8}{21.4} = 1.35$