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photoshop1234 [79]
3 years ago
7

A giraffe is 18 feet tall and has a 12 foot shadow. Mark has a 4 foot shadow. How tall is Mark?

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

6 foot

Step-by-step explanation:

so you can make a ratio out of it kinda

height : shadow height

18 : 12

1.5 : 1

so if its height : 4

the height would be 6 (4 + 2)

hope that makes sense :)

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Step-by-step explanation:

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4 years ago
X-(-15)=11 what is x
Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
70 minutes for 24 songs<br> =<br> [blank] minutes for 12 songs
s2008m [1.1K]

Answer:

35

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Pls answer quickly!!!
gizmo_the_mogwai [7]

Answer:

x = 90

y = 100

z = -10

Step-by-step explanation:

To find x and y in the above parallelogram ABCD as shown above, recall that one of the properties of a parallelogram is: the consecutive angles in a parallelogram are supplementary.

This means that the sum of angle A and angle B in the parallelogram ABCD = 180°.

Thus,

(x + 30)° + (x - 30)° = 180°

Solve for x

x + 30 + x - 30 = 180

x + x + 30 - 30 = 180

2x = 180

Divide both sides by 2

2x/2 = 180/2

x = 90

=>Find y:

Also, recall that opposite angles in a parallelogram are congruent.

This means, angle A and angle C in parallelogram ABCD above are equal.

Thus,

(x + 30)° = (y + 20)°

Plug in the value of x to solve for y

90 + 30 = y + 20

120 = y + 20

Subtract 20 from both sides

120 - 20 = y

100 = y

y = 100

=>Find z, if z = x - y

z = 90 - 100

z = -10

8 0
4 years ago
Ou have traveled 25 miles in 2 minutes and come to a standstill. What was your initial velocity?
Illusion [34]
If you traveled 25 miles in 2 minutes, your average speed was 25 miles per 2 minutes or 750 miles per hour. If your rate of deceleration was constant, your initial speed was two times 750 miles per hour or 1500 mph. 

<span>I do not have enough information to determine your initial velocity because I don't know what direction you were going, and velocity is speed with direction.</span>
4 0
3 years ago
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