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bogdanovich [222]
3 years ago
15

What line is perpendicular to y= 7/8x-2

Mathematics
1 answer:
belka [17]3 years ago
5 0
The slope for a line that's perpenficular is the resepical of each other
Ex. Slope: -2 Perpendicular Slope to 1st Line: \frac{1}{2}
so the perpendicular slope to 7/8 is -8/7
for y-intersecpt i would go on desmos(graping calculator website) and type in the equation y=-8/7x+b
Use the slider, and it you give you... You can't find the whole equation (y=mx+b). Because as long as the line has the slope of -8/7 it's perpenicular.
Did the problem tell you anything about a point that this new line goes through? Or no?
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Is 4 yards bigger than 13 feet
8_murik_8 [283]
1 yard = 3 feet

4 yards x 3 feet = 12 feet

12 feet is less than 13 feet


So False, 4 yards is <em>less than </em>13 feet

hope this helps
6 0
3 years ago
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CAN SOMEONE HELP ASAP PLEASE!! I'll give 50 points to the person that's correct!
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Is it a zero slope when the zero is the numerator of a fraction?? Ex:0/29
Mama L [17]
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5 0
4 years ago
Graciela was trying to solve the quadratic equation x2+2.5x−1.5=0 "I think I need to use the Quadratic Formula because of the de
drek231 [11]

Answer:

The answer to your question is  x² + 5/2x - 3/2 = 0

Step-by-step explanation:

Data

Quadratic equation           x² + 2.5x - 1.5 = 0

Process

1.- Convert the decimals into fractions

2.5 = 25/10 = 5/2

1.5 = 15/10 = 3/2

2.- Substitution

                                       x² + 5/2x - 3/2 = 0

3.- Conclusion

I rewrite the equation, now it is expressed in fractions. It could be solve by factoring.

7 0
3 years ago
This is confusing<br> (2x+y)^2−(x−2y)^2
Iteru [2.4K]

Answer:

{(2x + y)}^{2}  -  {(x - 2y)}^{2}

<  {(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2}  >

<  {(x - y)}^{2}  =  {x}^{2}  - 2xy +  {y}^{2}  >

{(2x)}^{2}  + 2(2x)(y) +  {(y)}^{2}  -  {(x)}^{2}  - 2(x)(2y) +  {(2y)}^{2}

{4x}^{2}  + 4xy +  {y}^{2}  -  {x}^{2}  - 4xy +  {4y}^{2}

{4x}^{2}   -  {x}^{2}  +  {4y}^{2}  +  {y}^{2}

= {3x}^{2}  +  {5y}^{2}

5 0
3 years ago
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